4y(y^2-y)+(2y+1)(2-1)=

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Solution for 4y(y^2-y)+(2y+1)(2-1)= equation:


Simplifying
4y(y2 + -1y) + (2y + 1)(2 + -1) = 0

Reorder the terms:
4y(-1y + y2) + (2y + 1)(2 + -1) = 0
(-1y * 4y + y2 * 4y) + (2y + 1)(2 + -1) = 0
(-4y2 + 4y3) + (2y + 1)(2 + -1) = 0

Reorder the terms:
-4y2 + 4y3 + (1 + 2y)(2 + -1) = 0

Combine like terms: 2 + -1 = 1
-4y2 + 4y3 + (1 + 2y)(1) = 0

Reorder the terms for easier multiplication:
-4y2 + 4y3 + 1(1 + 2y) = 0
-4y2 + 4y3 + (1 * 1 + 2y * 1) = 0
-4y2 + 4y3 + (1 + 2y) = 0

Reorder the terms:
1 + 2y + -4y2 + 4y3 = 0

Solving
1 + 2y + -4y2 + 4y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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